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Chapter 5: Arithmetic Progressions

NCERT Solutions for CBSE Class 10 Mathematics — 335 solved questions with detailed explanations.

335
Questions
4
Topics

Important Formulas

Solved Questions

Q1. The 10th term of AP 2, 7, 12, ... is:

Difficulty: Easy · Topic: nth Term of an AP

Solution

a=2, d=5. a₁₀ = 2+9(5) = 47.

Q2. Which is NOT an AP?

Difficulty: Easy · Topic: Introduction to AP

Solution

2,4,8,16 has ratios 2,2,2 (GP, not AP). Differences are 2,4,8 — not constant.

Q3. Find the sum of the first 129 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{129 \times 129+1}{2} = 8385\)

Q4. Find the sum of the first 146 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{146 \times 146+1}{2} = 10731\)

Q5. Find the sum of the first 125 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{125 \times 125+1}{2} = 7875\)

Q6. Find the sum of the first 19 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{19 \times 19+1}{2} = 190\)

Q7. Find the sum of the first 50 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{50 \times 50+1}{2} = 1275\)

Q8. Find the sum of the first 46 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{46 \times 46+1}{2} = 1081\)

Q9. Find the sum of the first 73 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{73 \times 73+1}{2} = 2701\)

Q10. Find the sum of the first 15 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{15 \times 15+1}{2} = 120\)

Q11. Find the sum of the first 20 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{20 \times 20+1}{2} = 210\)

Q12. Find the sum of the first 64 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{64 \times 64+1}{2} = 2080\)

Q13. Find the sum of the first 198 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{198 \times 198+1}{2} = 19701\)

Q14. Find the sum of the first 74 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{74 \times 74+1}{2} = 2775\)

Q15. Find the sum of the first 16 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{16 \times 16+1}{2} = 136\)

Q16. Find the sum of the first 13 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{13 \times 13+1}{2} = 91\)

Q17. Find the sum of the first 11 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{11 \times 11+1}{2} = 66\)

Q18. Find the sum of the first 89 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{89 \times 89+1}{2} = 4005\)

Q19. Find the sum of the first 181 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{181 \times 181+1}{2} = 16471\)

Q20. Find the sum of the first 34 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{34 \times 34+1}{2} = 595\)

Q21. Find the sum of the first 57 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{57 \times 57+1}{2} = 1653\)

Q22. Find the sum of the first 120 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{120 \times 120+1}{2} = 7260\)

Q23. Find the sum of the first 143 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{143 \times 143+1}{2} = 10296\)

Q24. Find the sum of the first 190 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{190 \times 190+1}{2} = 18145\)

Q25. Find the sum of the first 111 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{111 \times 111+1}{2} = 6216\)

Q26. Find the sum of the first 195 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{195 \times 195+1}{2} = 19110\)

Q27. Find the sum of the first 71 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{71 \times 71+1}{2} = 2556\)

Q28. Find the sum of the first 101 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{101 \times 101+1}{2} = 5151\)

Q29. Find the sum of the first 147 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{147 \times 147+1}{2} = 10878\)

Q30. Find the sum of the first 170 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{170 \times 170+1}{2} = 14535\)

Q31. Find the sum of the first 48 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{48 \times 48+1}{2} = 1176\)

Q32. Find the sum of the first 136 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{136 \times 136+1}{2} = 9316\)

Q33. Find the sum of the first 180 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{180 \times 180+1}{2} = 16290\)

Q34. Find the sum of the first 134 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{134 \times 134+1}{2} = 9045\)

Q35. Find the sum of the first 197 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{197 \times 197+1}{2} = 19503\)

Q36. Find the sum of the first 17 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{17 \times 17+1}{2} = 153\)

Q37. Find the sum of the first 127 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{127 \times 127+1}{2} = 8128\)

Q38. Find the sum of the first 175 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{175 \times 175+1}{2} = 15400\)

Q39. Find the sum of the first 103 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{103 \times 103+1}{2} = 5356\)

Q40. Find the sum of the first 33 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{33 \times 33+1}{2} = 561\)

Q41. Find the sum of the first 88 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{88 \times 88+1}{2} = 3916\)

Q42. Find the sum of the first 59 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{59 \times 59+1}{2} = 1770\)

Q43. Find the sum of the first 169 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{169 \times 169+1}{2} = 14365\)

Q44. Find the sum of the first 191 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{191 \times 191+1}{2} = 18336\)

Q45. Find the sum of the first 95 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{95 \times 95+1}{2} = 4560\)

Q46. Find the sum of the first 171 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{171 \times 171+1}{2} = 14706\)

Q47. Find the sum of the first 39 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{39 \times 39+1}{2} = 780\)

Q48. Find the sum of the first 117 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{117 \times 117+1}{2} = 6903\)

Q49. Find the sum of the first 188 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{188 \times 188+1}{2} = 17766\)

Q50. Find the sum of the first 157 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{157 \times 157+1}{2} = 12403\)

Q51. Find the sum of the first 94 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{94 \times 94+1}{2} = 4465\)

Q52. Find the sum of the first 35 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{35 \times 35+1}{2} = 630\)

Q53. Find the sum of the first 140 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{140 \times 140+1}{2} = 9870\)

Q54. Find the sum of the first 184 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{184 \times 184+1}{2} = 17020\)

Q55. Find the sum of the first 187 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{187 \times 187+1}{2} = 17578\)

Q56. Find the sum of the first 121 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{121 \times 121+1}{2} = 7381\)

Q57. Find the sum of the first 45 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{45 \times 45+1}{2} = 1035\)

Q58. Find the sum of the first 67 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{67 \times 67+1}{2} = 2278\)

Q59. Find the sum of the first 43 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{43 \times 43+1}{2} = 946\)

Q60. Find the sum of the first 166 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{166 \times 166+1}{2} = 13861\)

Q61. Find the sum of the first 44 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{44 \times 44+1}{2} = 990\)

Q62. Find the sum of the first 192 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{192 \times 192+1}{2} = 18528\)

Q63. Find the sum of the first 91 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{91 \times 91+1}{2} = 4186\)

Q64. Find the sum of the first 109 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{109 \times 109+1}{2} = 5995\)

Q65. Find the sum of the first 14 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{14 \times 14+1}{2} = 105\)

Q66. Find the sum of the first 87 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{87 \times 87+1}{2} = 3828\)

Q67. Find the sum of the first 68 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{68 \times 68+1}{2} = 2346\)

Q68. Find the sum of the first 154 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{154 \times 154+1}{2} = 11935\)

Q69. Find the sum of the first 165 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{165 \times 165+1}{2} = 13695\)

Q70. Find the sum of the first 112 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{112 \times 112+1}{2} = 6328\)

Q71. Find the sum of the first 69 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{69 \times 69+1}{2} = 2415\)

Q72. Find the sum of the first 163 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{163 \times 163+1}{2} = 13366\)

Q73. Find the sum of the first 160 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{160 \times 160+1}{2} = 12880\)

Q74. Find the sum of the first 61 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{61 \times 61+1}{2} = 1891\)

Q75. Find the sum of the first 52 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{52 \times 52+1}{2} = 1378\)

Q76. Find the sum of the first 41 natural numbers.

Difficulty: Easy · Topic: Sum of first n natural numbers

Solution

Sum of first n natural numbers \(= \frac{n(n+1)}{2}\)

\(= \frac{41 \times 41+1}{2} = 861\)

Q77. Which term of the AP 3, 15, 27, 39, ... will be 132 more than its 54th term?

Difficulty: Easy-Medium · Topic: nth Term of an AP

Solution

d=12. a₅₄ = 3+53(12) = 639. a₅₄+132 = 771 = 3+(n−1)12 → n−1=64 → n=65.

Q78. Find the sum of first 22 terms of the AP: 8, 3, −2, ...

Difficulty: Easy-Medium · Topic: Sum of First n Terms

Solution

a=8, d=−5. S₂₂ = 22/2[16+21(−5)] = 11[16−105] = 11(−89) = −979.

Q79. Find the 31st term of an AP whose 11th term is 38 and 16th term is 73.

Difficulty: Easy-Medium · Topic: nth Term of an AP

Solution

a+10d=38, a+15d=73 → 5d=35 → d=7. a=38−70=−32. a₃₁=−32+30(7)=178.

Q80. Find the sum of first 100 natural numbers.

Difficulty: Easy-Medium · Topic: Sum of First n Terms

Solution

S = 100/2(1+100) = 50 × 101 = 5050.

Q81. The first term of an AP is 5, last term is 45 and sum is 400. Number of terms is:

Difficulty: Easy-Medium · Topic: nth Term of an AP

Solution

Sₙ = n/2(a+l) → 400 = n/2(50) → n = 16.

Q82. If 2, x, 26 are in AP, then x =

Difficulty: Easy-Medium · Topic: Introduction to AP

Solution

x is the middle term: x = (2+26)/2 = 14.

Q83. Find the 12th term of the AP with first term \(a = 8\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{12} = 8 + (12-1) \times 9\)

\(= 8 + 107 - 8\) ... simplifying gives \(107\)

Q84. Find the 10th term of the AP with first term \(a = 6\) and common difference \(d = 4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{10} = 6 + (10-1) \times 4\)

\(= 6 + 42 - 6\) ... simplifying gives \(42\)

Q85. Find the 27th term of the AP with first term \(a = 15\) and common difference \(d = 10\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{27} = 15 + (27-1) \times 10\)

\(= 15 + 275 - 15\) ... simplifying gives \(275\)

Q86. Find the 17th term of the AP with first term \(a = 8\) and common difference \(d = 2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{17} = 8 + (17-1) \times 2\)

\(= 8 + 40 - 8\) ... simplifying gives \(40\)

Q87. Find the 8th term of the AP with first term \(a = 4\) and common difference \(d = 6\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{8} = 4 + (8-1) \times 6\)

\(= 4 + 46 - 4\) ... simplifying gives \(46\)

Q88. Find the 16th term of the AP with first term \(a = 11\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{16} = 11 + (16-1) \times 9\)

\(= 11 + 146 - 11\) ... simplifying gives \(146\)

Q89. Find the 18th term of the AP with first term \(a = 10\) and common difference \(d = 2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{18} = 10 + (18-1) \times 2\)

\(= 10 + 44 - 10\) ... simplifying gives \(44\)

Q90. Find the 29th term of the AP with first term \(a = 18\) and common difference \(d = 6\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{29} = 18 + (29-1) \times 6\)

\(= 18 + 186 - 18\) ... simplifying gives \(186\)

Q91. Find the 7th term of the AP with first term \(a = 10\) and common difference \(d = 1\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{7} = 10 + (7-1) \times 1\)

\(= 10 + 16 - 10\) ... simplifying gives \(16\)

Q92. Find the 5th term of the AP with first term \(a = 1\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{5} = 1 + (5-1) \times 9\)

\(= 1 + 37 - 1\) ... simplifying gives \(37\)

Q93. Find the 26th term of the AP with first term \(a = 14\) and common difference \(d = 8\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{26} = 14 + (26-1) \times 8\)

\(= 14 + 214 - 14\) ... simplifying gives \(214\)

Q94. Find the 17th term of the AP with first term \(a = 20\) and common difference \(d = 5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{17} = 20 + (17-1) \times 5\)

\(= 20 + 100 - 20\) ... simplifying gives \(100\)

Q95. Find the 17th term of the AP with first term \(a = 19\) and common difference \(d = -1\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{17} = 19 + (17-1) \times -1\)

\(= 19 + 3 - 19\) ... simplifying gives \(3\)

Q96. Find the 16th term of the AP with first term \(a = 14\) and common difference \(d = 1\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{16} = 14 + (16-1) \times 1\)

\(= 14 + 29 - 14\) ... simplifying gives \(29\)

Q97. Find the 25th term of the AP with first term \(a = 16\) and common difference \(d = -3\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{25} = 16 + (25-1) \times -3\)

\(= 16 + -56 - 16\) ... simplifying gives \(-56\)

Q98. Find the 26th term of the AP with first term \(a = 4\) and common difference \(d = -5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{26} = 4 + (26-1) \times -5\)

\(= 4 + -121 - 4\) ... simplifying gives \(-121\)

Q99. Find the 9th term of the AP with first term \(a = 8\) and common difference \(d = 2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{9} = 8 + (9-1) \times 2\)

\(= 8 + 24 - 8\) ... simplifying gives \(24\)

Q100. Find the 23th term of the AP with first term \(a = 19\) and common difference \(d = 8\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{23} = 19 + (23-1) \times 8\)

\(= 19 + 195 - 19\) ... simplifying gives \(195\)

Q101. Find the 30th term of the AP with first term \(a = 10\) and common difference \(d = -3\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{30} = 10 + (30-1) \times -3\)

\(= 10 + -77 - 10\) ... simplifying gives \(-77\)

Q102. Find the 16th term of the AP with first term \(a = 8\) and common difference \(d = 10\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{16} = 8 + (16-1) \times 10\)

\(= 8 + 158 - 8\) ... simplifying gives \(158\)

Q103. Find the 27th term of the AP with first term \(a = 9\) and common difference \(d = 3\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{27} = 9 + (27-1) \times 3\)

\(= 9 + 87 - 9\) ... simplifying gives \(87\)

Q104. Find the 18th term of the AP with first term \(a = 17\) and common difference \(d = -1\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{18} = 17 + (18-1) \times -1\)

\(= 17 + 0 - 17\) ... simplifying gives \(0\)

Q105. Find the 29th term of the AP with first term \(a = 11\) and common difference \(d = 6\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{29} = 11 + (29-1) \times 6\)

\(= 11 + 179 - 11\) ... simplifying gives \(179\)

Q106. Find the 25th term of the AP with first term \(a = 11\) and common difference \(d = -5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{25} = 11 + (25-1) \times -5\)

\(= 11 + -109 - 11\) ... simplifying gives \(-109\)

Q107. Find the 18th term of the AP with first term \(a = 15\) and common difference \(d = -5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{18} = 15 + (18-1) \times -5\)

\(= 15 + -70 - 15\) ... simplifying gives \(-70\)

Q108. Find the 29th term of the AP with first term \(a = 3\) and common difference \(d = 8\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{29} = 3 + (29-1) \times 8\)

\(= 3 + 227 - 3\) ... simplifying gives \(227\)

Q109. Find the 23th term of the AP with first term \(a = 19\) and common difference \(d = 0\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{23} = 19 + (23-1) \times 0\)

\(= 19 + 19 - 19\) ... simplifying gives \(19\)

Q110. Find the 29th term of the AP with first term \(a = 11\) and common difference \(d = 7\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{29} = 11 + (29-1) \times 7\)

\(= 11 + 207 - 11\) ... simplifying gives \(207\)

Q111. Find the 14th term of the AP with first term \(a = 18\) and common difference \(d = 7\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{14} = 18 + (14-1) \times 7\)

\(= 18 + 109 - 18\) ... simplifying gives \(109\)

Q112. Find the 17th term of the AP with first term \(a = 16\) and common difference \(d = -5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{17} = 16 + (17-1) \times -5\)

\(= 16 + -64 - 16\) ... simplifying gives \(-64\)

Q113. Find the 25th term of the AP with first term \(a = 2\) and common difference \(d = 5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{25} = 2 + (25-1) \times 5\)

\(= 2 + 122 - 2\) ... simplifying gives \(122\)

Q114. Find the 25th term of the AP with first term \(a = 4\) and common difference \(d = -2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{25} = 4 + (25-1) \times -2\)

\(= 4 + -44 - 4\) ... simplifying gives \(-44\)

Q115. Find the 24th term of the AP with first term \(a = 10\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{24} = 10 + (24-1) \times 9\)

\(= 10 + 217 - 10\) ... simplifying gives \(217\)

Q116. Find the 27th term of the AP with first term \(a = 19\) and common difference \(d = -4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{27} = 19 + (27-1) \times -4\)

\(= 19 + -85 - 19\) ... simplifying gives \(-85\)

Q117. Find the 28th term of the AP with first term \(a = 1\) and common difference \(d = -2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{28} = 1 + (28-1) \times -2\)

\(= 1 + -53 - 1\) ... simplifying gives \(-53\)

Q118. Find the 27th term of the AP with first term \(a = 17\) and common difference \(d = 0\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{27} = 17 + (27-1) \times 0\)

\(= 17 + 17 - 17\) ... simplifying gives \(17\)

Q119. Find the 8th term of the AP with first term \(a = 1\) and common difference \(d = 3\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{8} = 1 + (8-1) \times 3\)

\(= 1 + 22 - 1\) ... simplifying gives \(22\)

Q120. Find the 28th term of the AP with first term \(a = 16\) and common difference \(d = 5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{28} = 16 + (28-1) \times 5\)

\(= 16 + 151 - 16\) ... simplifying gives \(151\)

Q121. Find the 21th term of the AP with first term \(a = 19\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{21} = 19 + (21-1) \times 9\)

\(= 19 + 199 - 19\) ... simplifying gives \(199\)

Q122. Find the 30th term of the AP with first term \(a = 20\) and common difference \(d = 7\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{30} = 20 + (30-1) \times 7\)

\(= 20 + 223 - 20\) ... simplifying gives \(223\)

Q123. Find the 7th term of the AP with first term \(a = 7\) and common difference \(d = -4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{7} = 7 + (7-1) \times -4\)

\(= 7 + -17 - 7\) ... simplifying gives \(-17\)

Q124. Find the 5th term of the AP with first term \(a = 5\) and common difference \(d = 10\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{5} = 5 + (5-1) \times 10\)

\(= 5 + 45 - 5\) ... simplifying gives \(45\)

Q125. Find the 25th term of the AP with first term \(a = 11\) and common difference \(d = 5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{25} = 11 + (25-1) \times 5\)

\(= 11 + 131 - 11\) ... simplifying gives \(131\)

Q126. Find the 30th term of the AP with first term \(a = 17\) and common difference \(d = 1\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{30} = 17 + (30-1) \times 1\)

\(= 17 + 46 - 17\) ... simplifying gives \(46\)

Q127. Find the 12th term of the AP with first term \(a = 3\) and common difference \(d = 6\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{12} = 3 + (12-1) \times 6\)

\(= 3 + 69 - 3\) ... simplifying gives \(69\)

Q128. Find the 9th term of the AP with first term \(a = 12\) and common difference \(d = -3\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{9} = 12 + (9-1) \times -3\)

\(= 12 + -12 - 12\) ... simplifying gives \(-12\)

Q129. Find the 8th term of the AP with first term \(a = 20\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{8} = 20 + (8-1) \times 9\)

\(= 20 + 83 - 20\) ... simplifying gives \(83\)

Q130. Find the 12th term of the AP with first term \(a = 18\) and common difference \(d = 4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{12} = 18 + (12-1) \times 4\)

\(= 18 + 62 - 18\) ... simplifying gives \(62\)

Q131. Find the 9th term of the AP with first term \(a = 12\) and common difference \(d = -2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{9} = 12 + (9-1) \times -2\)

\(= 12 + -4 - 12\) ... simplifying gives \(-4\)

Q132. Find the 25th term of the AP with first term \(a = 14\) and common difference \(d = 1\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{25} = 14 + (25-1) \times 1\)

\(= 14 + 38 - 14\) ... simplifying gives \(38\)

Q133. Find the 11th term of the AP with first term \(a = 4\) and common difference \(d = 10\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{11} = 4 + (11-1) \times 10\)

\(= 4 + 104 - 4\) ... simplifying gives \(104\)

Q134. Find the 26th term of the AP with first term \(a = 7\) and common difference \(d = 1\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{26} = 7 + (26-1) \times 1\)

\(= 7 + 32 - 7\) ... simplifying gives \(32\)

Q135. Find the 9th term of the AP with first term \(a = 8\) and common difference \(d = 4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{9} = 8 + (9-1) \times 4\)

\(= 8 + 40 - 8\) ... simplifying gives \(40\)

Q136. Find the 5th term of the AP with first term \(a = 12\) and common difference \(d = -4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{5} = 12 + (5-1) \times -4\)

\(= 12 + -4 - 12\) ... simplifying gives \(-4\)

Q137. Find the 13th term of the AP with first term \(a = 19\) and common difference \(d = 6\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{13} = 19 + (13-1) \times 6\)

\(= 19 + 91 - 19\) ... simplifying gives \(91\)

Q138. Find the 25th term of the AP with first term \(a = 1\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{25} = 1 + (25-1) \times 9\)

\(= 1 + 217 - 1\) ... simplifying gives \(217\)

Q139. Find the 24th term of the AP with first term \(a = 12\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{24} = 12 + (24-1) \times 9\)

\(= 12 + 219 - 12\) ... simplifying gives \(219\)

Q140. Find the 30th term of the AP with first term \(a = 11\) and common difference \(d = 0\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{30} = 11 + (30-1) \times 0\)

\(= 11 + 11 - 11\) ... simplifying gives \(11\)

Q141. Find the 20th term of the AP with first term \(a = 3\) and common difference \(d = -4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{20} = 3 + (20-1) \times -4\)

\(= 3 + -73 - 3\) ... simplifying gives \(-73\)

Q142. Find the 27th term of the AP with first term \(a = 17\) and common difference \(d = -3\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{27} = 17 + (27-1) \times -3\)

\(= 17 + -61 - 17\) ... simplifying gives \(-61\)

Q143. Find the 15th term of the AP with first term \(a = 10\) and common difference \(d = 2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{15} = 10 + (15-1) \times 2\)

\(= 10 + 38 - 10\) ... simplifying gives \(38\)

Q144. Find the 19th term of the AP with first term \(a = 5\) and common difference \(d = 2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{19} = 5 + (19-1) \times 2\)

\(= 5 + 41 - 5\) ... simplifying gives \(41\)

Q145. Find the 14th term of the AP with first term \(a = 7\) and common difference \(d = 0\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{14} = 7 + (14-1) \times 0\)

\(= 7 + 7 - 7\) ... simplifying gives \(7\)

Q146. Find the 28th term of the AP with first term \(a = 12\) and common difference \(d = 4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{28} = 12 + (28-1) \times 4\)

\(= 12 + 120 - 12\) ... simplifying gives \(120\)

Q147. Find the 24th term of the AP with first term \(a = 15\) and common difference \(d = 2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{24} = 15 + (24-1) \times 2\)

\(= 15 + 61 - 15\) ... simplifying gives \(61\)

Q148. Find the 24th term of the AP with first term \(a = 19\) and common difference \(d = -5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{24} = 19 + (24-1) \times -5\)

\(= 19 + -96 - 19\) ... simplifying gives \(-96\)

Q149. Find the 12th term of the AP with first term \(a = 13\) and common difference \(d = 4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{12} = 13 + (12-1) \times 4\)

\(= 13 + 57 - 13\) ... simplifying gives \(57\)

Q150. Find the 27th term of the AP with first term \(a = 19\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{27} = 19 + (27-1) \times 9\)

\(= 19 + 253 - 19\) ... simplifying gives \(253\)

Q151. Find the 28th term of the AP with first term \(a = 3\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{28} = 3 + (28-1) \times 9\)

\(= 3 + 246 - 3\) ... simplifying gives \(246\)

Q152. Find the 22th term of the AP with first term \(a = 2\) and common difference \(d = 10\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{22} = 2 + (22-1) \times 10\)

\(= 2 + 212 - 2\) ... simplifying gives \(212\)

Q153. Find the 9th term of the AP with first term \(a = 1\) and common difference \(d = 3\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{9} = 1 + (9-1) \times 3\)

\(= 1 + 25 - 1\) ... simplifying gives \(25\)

Q154. Find the 21th term of the AP with first term \(a = 9\) and common difference \(d = 5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{21} = 9 + (21-1) \times 5\)

\(= 9 + 109 - 9\) ... simplifying gives \(109\)

Q155. Find the 22th term of the AP with first term \(a = 14\) and common difference \(d = -5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{22} = 14 + (22-1) \times -5\)

\(= 14 + -91 - 14\) ... simplifying gives \(-91\)

Q156. Find the 8th term of the AP with first term \(a = 5\) and common difference \(d = 4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{8} = 5 + (8-1) \times 4\)

\(= 5 + 33 - 5\) ... simplifying gives \(33\)

Q157. Find the 18th term of the AP with first term \(a = 3\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{18} = 3 + (18-1) \times 9\)

\(= 3 + 156 - 3\) ... simplifying gives \(156\)

Q158. Find the 28th term of the AP with first term \(a = 17\) and common difference \(d = 0\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{28} = 17 + (28-1) \times 0\)

\(= 17 + 17 - 17\) ... simplifying gives \(17\)

Q159. Find the 24th term of the AP with first term \(a = 14\) and common difference \(d = -3\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{24} = 14 + (24-1) \times -3\)

\(= 14 + -55 - 14\) ... simplifying gives \(-55\)

Q160. Find the 9th term of the AP with first term \(a = 2\) and common difference \(d = 7\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{9} = 2 + (9-1) \times 7\)

\(= 2 + 58 - 2\) ... simplifying gives \(58\)

Q161. Find the 15th term of the AP with first term \(a = 5\) and common difference \(d = -1\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{15} = 5 + (15-1) \times -1\)

\(= 5 + -9 - 5\) ... simplifying gives \(-9\)

Q162. Find the 12th term of the AP with first term \(a = 15\) and common difference \(d = -3\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{12} = 15 + (12-1) \times -3\)

\(= 15 + -18 - 15\) ... simplifying gives \(-18\)

Q163. Find the 15th term of the AP with first term \(a = 3\) and common difference \(d = -4\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{15} = 3 + (15-1) \times -4\)

\(= 3 + -53 - 3\) ... simplifying gives \(-53\)

Q164. Find the 17th term of the AP with first term \(a = 7\) and common difference \(d = -5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{17} = 7 + (17-1) \times -5\)

\(= 7 + -73 - 7\) ... simplifying gives \(-73\)

Q165. Find the 30th term of the AP with first term \(a = 20\) and common difference \(d = 9\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{30} = 20 + (30-1) \times 9\)

\(= 20 + 281 - 20\) ... simplifying gives \(281\)

Q166. Find the 14th term of the AP with first term \(a = 8\) and common difference \(d = -5\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{14} = 8 + (14-1) \times -5\)

\(= 8 + -57 - 8\) ... simplifying gives \(-57\)

Q167. Find the 29th term of the AP with first term \(a = 13\) and common difference \(d = -2\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{29} = 13 + (29-1) \times -2\)

\(= 13 + -43 - 13\) ... simplifying gives \(-43\)

Q168. Find the 12th term of the AP with first term \(a = 15\) and common difference \(d = 10\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{12} = 15 + (12-1) \times 10\)

\(= 15 + 125 - 15\) ... simplifying gives \(125\)

Q169. Find the 15th term of the AP with first term \(a = 1\) and common difference \(d = 7\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{15} = 1 + (15-1) \times 7\)

\(= 1 + 99 - 1\) ... simplifying gives \(99\)

Q170. Find the 6th term of the AP with first term \(a = 1\) and common difference \(d = 6\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{6} = 1 + (6-1) \times 6\)

\(= 1 + 31 - 1\) ... simplifying gives \(31\)

Q171. Find the 7th term of the AP with first term \(a = 13\) and common difference \(d = 0\).

Difficulty: Easy-Medium · Topic: Finding the nth term

Solution

\(a_n = a + (n-1)d\)

\(a_{7} = 13 + (7-1) \times 0\)

\(= 13 + 13 - 13\) ... simplifying gives \(13\)

Q172. How many terms of the AP 9, 17, 25, ... must be taken to give a sum of 636?

Difficulty: Medium · Topic: Sum of First n Terms

Solution

a=9, d=8. Sₙ = n/2[18+(n−1)8] = n/2[8n+10] = n(4n+5).

4n²+5n=636 → 4n²+5n−636=0 → (4n+53)(n−12)=0. n=12.

Q173. The sum of the 4th and 8th terms of an AP is 24, and the sum of the 6th and 10th terms is 44. Find the first three terms.

Difficulty: Medium · Topic: nth Term of an AP

Solution

a₄+a₈ = 2a+10d = 24 ... (i). a₆+a₁₀ = 2a+14d = 44 ... (ii).

Subtract: 4d=20 → d=5. 2a+50=24 → a=−13. AP: −13, −8, −3.

Q174. Find the sum of integers from 1 to 100 that are divisible by 2 or 5.

Difficulty: Medium · Topic: Sum of First n Terms

Solution

Sum div by 2: 2+4+...+100 = 50/2(2+100)=2550.

Sum div by 5: 5+10+...+100 = 20/2(5+100)=1050.

Sum div by 10: 10+20+...+100 = 10/2(10+100)=550.

By inclusion-exclusion: 2550+1050−550 = 3050.

Q175. If the 3rd and 9th terms of an AP are 4 and −8 respectively, which term is zero?

Difficulty: Medium · Topic: nth Term of an AP

Solution

a+2d=4, a+8d=−8 → 6d=−12 → d=−2. a=8. aₙ=0 → 8+(n−1)(−2)=0 → n=5.

Q176. Find the sum of the first 24 terms of the AP if a₁₂ = −13 and the sum of first four terms is 24.

Difficulty: Medium · Topic: Sum of First n Terms

Solution

a+11d=−13 ... (i). S₄ = 4/2(2a+3d) = 2(2a+3d) = 24 → 2a+3d=12 ... (ii).

From (i): a=−13−11d. Substitute: −26−22d+3d=12 → −19d=38 → d=−2. a=−13+22=9.

S₂₄ = 24/2[18+23(−2)] = 12[18−46] = 12(−28) = −336.

Wait, let me recheck: S₂₄ = 12[2(9)+23(−2)] = 12[18−46] = 12(−28) = −336.

Hmm, let me verify a₁₂: 9+11(−2) = 9−22 = −13 ✓. S₄ = 2[18+3(−2)] = 2(12) = 24 ✓.

S₂₄ = −336.

Q177. The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

Difficulty: Medium · Topic: nth Term of an AP

Solution

a₁₇−a₁₀ = 7d = 7 → d = 1.

Q178. Find the sum of all two-digit odd positive numbers.

Difficulty: Medium · Topic: Sum of First n Terms

Solution

AP: 11, 13, 15, ..., 99. a=11, d=2, l=99. n = (99−11)/2+1 = 45. S = 45/2(11+99) = 45×55 = 2475.

Q179. Find the sum of the first 22 terms of the AP: \(a = 12\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{22} = \frac{22}{2}[2 \times 12 + (22-1) \times 4]\)

\(= 1188\)

Q180. Find the sum of the first 11 terms of the AP: \(a = 2\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{11} = \frac{11}{2}[2 \times 2 + (11-1) \times 7]\)

\(= 407\)

Q181. Find the sum of the first 23 terms of the AP: \(a = 13\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{23} = \frac{23}{2}[2 \times 13 + (23-1) \times 1]\)

\(= 552\)

Q182. Find the sum of the first 6 terms of the AP: \(a = 9\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{6} = \frac{6}{2}[2 \times 9 + (6-1) \times 6]\)

\(= 144\)

Q183. Find the sum of the first 7 terms of the AP: \(a = 8\), \(d = 2\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{7} = \frac{7}{2}[2 \times 8 + (7-1) \times 2]\)

\(= 98\)

Q184. Find the sum of the first 25 terms of the AP: \(a = 9\), \(d = 3\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{25} = \frac{25}{2}[2 \times 9 + (25-1) \times 3]\)

\(= 1125\)

Q185. Find the sum of the first 25 terms of the AP: \(a = 11\), \(d = 3\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{25} = \frac{25}{2}[2 \times 11 + (25-1) \times 3]\)

\(= 1175\)

Q186. Find the sum of the first 6 terms of the AP: \(a = 14\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{6} = \frac{6}{2}[2 \times 14 + (6-1) \times 5]\)

\(= 159\)

Q187. Find the sum of the first 25 terms of the AP: \(a = 6\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{25} = \frac{25}{2}[2 \times 6 + (25-1) \times 4]\)

\(= 1350\)

Q188. Find the sum of the first 7 terms of the AP: \(a = 7\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{7} = \frac{7}{2}[2 \times 7 + (7-1) \times 1]\)

\(= 70\)

Q189. Find the sum of the first 19 terms of the AP: \(a = 6\), \(d = 8\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{19} = \frac{19}{2}[2 \times 6 + (19-1) \times 8]\)

\(= 1482\)

Q190. Find the sum of the first 6 terms of the AP: \(a = 1\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{6} = \frac{6}{2}[2 \times 1 + (6-1) \times 6]\)

\(= 96\)

Q191. Find the sum of the first 17 terms of the AP: \(a = 12\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{17} = \frac{17}{2}[2 \times 12 + (17-1) \times 4]\)

\(= 748\)

Q192. Find the sum of the first 5 terms of the AP: \(a = 13\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{5} = \frac{5}{2}[2 \times 13 + (5-1) \times 1]\)

\(= 75\)

Q193. Find the sum of the first 17 terms of the AP: \(a = 7\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{17} = \frac{17}{2}[2 \times 7 + (17-1) \times 7]\)

\(= 1071\)

Q194. Find the sum of the first 21 terms of the AP: \(a = 4\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{21} = \frac{21}{2}[2 \times 4 + (21-1) \times 1]\)

\(= 294\)

Q195. Find the sum of the first 21 terms of the AP: \(a = 3\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{21} = \frac{21}{2}[2 \times 3 + (21-1) \times 7]\)

\(= 1533\)

Q196. Find the sum of the first 12 terms of the AP: \(a = 15\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{12} = \frac{12}{2}[2 \times 15 + (12-1) \times 4]\)

\(= 444\)

Q197. Find the sum of the first 18 terms of the AP: \(a = 14\), \(d = 8\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{18} = \frac{18}{2}[2 \times 14 + (18-1) \times 8]\)

\(= 1476\)

Q198. Find the sum of the first 13 terms of the AP: \(a = 5\), \(d = 2\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{13} = \frac{13}{2}[2 \times 5 + (13-1) \times 2]\)

\(= 221\)

Q199. Find the sum of the first 16 terms of the AP: \(a = 12\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{16} = \frac{16}{2}[2 \times 12 + (16-1) \times 5]\)

\(= 792\)

Q200. Find the sum of the first 14 terms of the AP: \(a = 6\), \(d = 8\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{14} = \frac{14}{2}[2 \times 6 + (14-1) \times 8]\)

\(= 812\)

Q201. Find the sum of the first 13 terms of the AP: \(a = 8\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{13} = \frac{13}{2}[2 \times 8 + (13-1) \times 6]\)

\(= 572\)

Q202. Find the sum of the first 20 terms of the AP: \(a = 11\), \(d = 3\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{20} = \frac{20}{2}[2 \times 11 + (20-1) \times 3]\)

\(= 790\)

Q203. Find the sum of the first 11 terms of the AP: \(a = 13\), \(d = 3\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{11} = \frac{11}{2}[2 \times 13 + (11-1) \times 3]\)

\(= 308\)

Q204. Find the sum of the first 13 terms of the AP: \(a = 1\), \(d = 8\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{13} = \frac{13}{2}[2 \times 1 + (13-1) \times 8]\)

\(= 637\)

Q205. Find the sum of the first 23 terms of the AP: \(a = 4\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{23} = \frac{23}{2}[2 \times 4 + (23-1) \times 6]\)

\(= 1610\)

Q206. Find the sum of the first 20 terms of the AP: \(a = 5\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{20} = \frac{20}{2}[2 \times 5 + (20-1) \times 4]\)

\(= 860\)

Q207. Find the sum of the first 7 terms of the AP: \(a = 10\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{7} = \frac{7}{2}[2 \times 10 + (7-1) \times 4]\)

\(= 154\)

Q208. Find the sum of the first 10 terms of the AP: \(a = 14\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{10} = \frac{10}{2}[2 \times 14 + (10-1) \times 4]\)

\(= 320\)

Q209. Find the compound interest on Rs 8000 at 10% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 8000\left(1 + \frac{10}{100}\right)^{1}\)

CI = A - P = 800.0

Q210. Find the compound interest on Rs 15000 at 10% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 15000\left(1 + \frac{10}{100}\right)^{2}\)

CI = A - P = 3150.0

Q211. Find the compound interest on Rs 5000 at 20% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 5000\left(1 + \frac{20}{100}\right)^{2}\)

CI = A - P = 2200.0

Q212. Find the compound interest on Rs 8000 at 5% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 8000\left(1 + \frac{5}{100}\right)^{1}\)

CI = A - P = 400.0

Q213. Find the compound interest on Rs 1000 at 10% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 1000\left(1 + \frac{10}{100}\right)^{3}\)

CI = A - P = 331.0

Q214. Find the compound interest on Rs 2000 at 15% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 2000\left(1 + \frac{15}{100}\right)^{1}\)

CI = A - P = 300.0

Q215. Find the compound interest on Rs 5000 at 12% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 5000\left(1 + \frac{12}{100}\right)^{2}\)

CI = A - P = 1272.0

Q216. Find the compound interest on Rs 8000 at 5% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 8000\left(1 + \frac{5}{100}\right)^{3}\)

CI = A - P = 1261.0

Q217. Find the compound interest on Rs 15000 at 5% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 15000\left(1 + \frac{5}{100}\right)^{3}\)

CI = A - P = 2364.38

Q218. Find the compound interest on Rs 25000 at 20% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 25000\left(1 + \frac{20}{100}\right)^{3}\)

CI = A - P = 18200.0

Q219. Find the compound interest on Rs 15000 at 8% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 15000\left(1 + \frac{8}{100}\right)^{3}\)

CI = A - P = 3895.68

Q220. Find the compound interest on Rs 15000 at 15% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 15000\left(1 + \frac{15}{100}\right)^{1}\)

CI = A - P = 2250.0

Q221. Find the compound interest on Rs 1000 at 20% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 1000\left(1 + \frac{20}{100}\right)^{2}\)

CI = A - P = 440.0

Q222. Find the compound interest on Rs 5000 at 5% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 5000\left(1 + \frac{5}{100}\right)^{3}\)

CI = A - P = 788.13

Q223. Find the compound interest on Rs 20000 at 10% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{10}{100}\right)^{2}\)

CI = A - P = 4200.0

Q224. Find the compound interest on Rs 8000 at 8% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 8000\left(1 + \frac{8}{100}\right)^{3}\)

CI = A - P = 2077.7

Q225. Find the compound interest on Rs 1000 at 12% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 1000\left(1 + \frac{12}{100}\right)^{1}\)

CI = A - P = 120.0

Q226. Find the compound interest on Rs 10000 at 20% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 10000\left(1 + \frac{20}{100}\right)^{2}\)

CI = A - P = 4400.0

Q227. Find the compound interest on Rs 20000 at 5% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{5}{100}\right)^{3}\)

CI = A - P = 3152.5

Q228. Find the compound interest on Rs 1000 at 20% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 1000\left(1 + \frac{20}{100}\right)^{3}\)

CI = A - P = 728.0

Q229. Find the compound interest on Rs 2000 at 12% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 2000\left(1 + \frac{12}{100}\right)^{2}\)

CI = A - P = 508.8

Q230. Find the compound interest on Rs 10000 at 15% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 10000\left(1 + \frac{15}{100}\right)^{3}\)

CI = A - P = 5208.75

Q231. Find the compound interest on Rs 10000 at 20% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 10000\left(1 + \frac{20}{100}\right)^{3}\)

CI = A - P = 7280.0

Q232. Find the compound interest on Rs 8000 at 5% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 8000\left(1 + \frac{5}{100}\right)^{2}\)

CI = A - P = 820.0

Q233. Find the compound interest on Rs 8000 at 12% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 8000\left(1 + \frac{12}{100}\right)^{1}\)

CI = A - P = 960.0

Q234. Find the compound interest on Rs 25000 at 15% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 25000\left(1 + \frac{15}{100}\right)^{1}\)

CI = A - P = 3750.0

Q235. Find the compound interest on Rs 5000 at 10% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 5000\left(1 + \frac{10}{100}\right)^{1}\)

CI = A - P = 500.0

Q236. Find the sum of the first 22 terms of the AP: \(a = 5\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{22} = \frac{22}{2}[2 \times 5 + (22-1) \times 6]\)

\(= 1496\)

Q237. Find the sum of the first 18 terms of the AP: \(a = 1\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{18} = \frac{18}{2}[2 \times 1 + (18-1) \times 1]\)

\(= 171\)

Q238. Find the sum of the first 13 terms of the AP: \(a = 3\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{13} = \frac{13}{2}[2 \times 3 + (13-1) \times 7]\)

\(= 585\)

Q239. Find the sum of the first 14 terms of the AP: \(a = 10\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{14} = \frac{14}{2}[2 \times 10 + (14-1) \times 5]\)

\(= 595\)

Q240. Find the sum of the first 5 terms of the AP: \(a = 6\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{5} = \frac{5}{2}[2 \times 6 + (5-1) \times 1]\)

\(= 40\)

Q241. Find the sum of the first 12 terms of the AP: \(a = 14\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{12} = \frac{12}{2}[2 \times 14 + (12-1) \times 6]\)

\(= 564\)

Q242. Find the sum of the first 5 terms of the AP: \(a = 2\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{5} = \frac{5}{2}[2 \times 2 + (5-1) \times 7]\)

\(= 80\)

Q243. Find the sum of the first 19 terms of the AP: \(a = 14\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{19} = \frac{19}{2}[2 \times 14 + (19-1) \times 6]\)

\(= 1292\)

Q244. Find the sum of the first 11 terms of the AP: \(a = 7\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{11} = \frac{11}{2}[2 \times 7 + (11-1) \times 6]\)

\(= 407\)

Q245. Find the sum of the first 14 terms of the AP: \(a = 5\), \(d = 8\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{14} = \frac{14}{2}[2 \times 5 + (14-1) \times 8]\)

\(= 798\)

Q246. Find the sum of the first 18 terms of the AP: \(a = 4\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{18} = \frac{18}{2}[2 \times 4 + (18-1) \times 6]\)

\(= 990\)

Q247. Find the sum of the first 14 terms of the AP: \(a = 6\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{14} = \frac{14}{2}[2 \times 6 + (14-1) \times 4]\)

\(= 448\)

Q248. Find the sum of the first 22 terms of the AP: \(a = 10\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{22} = \frac{22}{2}[2 \times 10 + (22-1) \times 5]\)

\(= 1375\)

Q249. Find the sum of the first 15 terms of the AP: \(a = 14\), \(d = 8\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{15} = \frac{15}{2}[2 \times 14 + (15-1) \times 8]\)

\(= 1050\)

Q250. Find the sum of the first 23 terms of the AP: \(a = 12\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{23} = \frac{23}{2}[2 \times 12 + (23-1) \times 4]\)

\(= 1288\)

Q251. Find the sum of the first 21 terms of the AP: \(a = 2\), \(d = 2\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{21} = \frac{21}{2}[2 \times 2 + (21-1) \times 2]\)

\(= 462\)

Q252. Find the sum of the first 17 terms of the AP: \(a = 4\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{17} = \frac{17}{2}[2 \times 4 + (17-1) \times 6]\)

\(= 884\)

Q253. Find the sum of the first 6 terms of the AP: \(a = 15\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{6} = \frac{6}{2}[2 \times 15 + (6-1) \times 1]\)

\(= 105\)

Q254. Find the sum of the first 17 terms of the AP: \(a = 12\), \(d = 3\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{17} = \frac{17}{2}[2 \times 12 + (17-1) \times 3]\)

\(= 612\)

Q255. Find the sum of the first 25 terms of the AP: \(a = 3\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{25} = \frac{25}{2}[2 \times 3 + (25-1) \times 5]\)

\(= 1575\)

Q256. Find the sum of the first 7 terms of the AP: \(a = 14\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{7} = \frac{7}{2}[2 \times 14 + (7-1) \times 5]\)

\(= 203\)

Q257. Find the sum of the first 20 terms of the AP: \(a = 5\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{20} = \frac{20}{2}[2 \times 5 + (20-1) \times 7]\)

\(= 1430\)

Q258. Find the sum of the first 14 terms of the AP: \(a = 12\), \(d = 2\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{14} = \frac{14}{2}[2 \times 12 + (14-1) \times 2]\)

\(= 350\)

Q259. Find the sum of the first 10 terms of the AP: \(a = 10\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{10} = \frac{10}{2}[2 \times 10 + (10-1) \times 7]\)

\(= 415\)

Q260. Find the sum of the first 12 terms of the AP: \(a = 15\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{12} = \frac{12}{2}[2 \times 15 + (12-1) \times 6]\)

\(= 576\)

Q261. Find the sum of the first 21 terms of the AP: \(a = 4\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{21} = \frac{21}{2}[2 \times 4 + (21-1) \times 4]\)

\(= 924\)

Q262. Find the sum of the first 16 terms of the AP: \(a = 13\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{16} = \frac{16}{2}[2 \times 13 + (16-1) \times 5]\)

\(= 808\)

Q263. Find the sum of the first 15 terms of the AP: \(a = 10\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{15} = \frac{15}{2}[2 \times 10 + (15-1) \times 5]\)

\(= 675\)

Q264. Find the sum of the first 11 terms of the AP: \(a = 11\), \(d = 3\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{11} = \frac{11}{2}[2 \times 11 + (11-1) \times 3]\)

\(= 286\)

Q265. Find the sum of the first 9 terms of the AP: \(a = 1\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{9} = \frac{9}{2}[2 \times 1 + (9-1) \times 6]\)

\(= 225\)

Q266. Find the sum of the first 5 terms of the AP: \(a = 7\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{5} = \frac{5}{2}[2 \times 7 + (5-1) \times 7]\)

\(= 105\)

Q267. Find the sum of the first 15 terms of the AP: \(a = 2\), \(d = 3\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{15} = \frac{15}{2}[2 \times 2 + (15-1) \times 3]\)

\(= 345\)

Q268. Find the sum of the first 18 terms of the AP: \(a = 12\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{18} = \frac{18}{2}[2 \times 12 + (18-1) \times 7]\)

\(= 1287\)

Q269. Find the sum of the first 16 terms of the AP: \(a = 4\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{16} = \frac{16}{2}[2 \times 4 + (16-1) \times 5]\)

\(= 664\)

Q270. Find the sum of the first 13 terms of the AP: \(a = 3\), \(d = 2\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{13} = \frac{13}{2}[2 \times 3 + (13-1) \times 2]\)

\(= 195\)

Q271. Find the sum of the first 11 terms of the AP: \(a = 13\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{11} = \frac{11}{2}[2 \times 13 + (11-1) \times 5]\)

\(= 418\)

Q272. Find the sum of the first 20 terms of the AP: \(a = 15\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{20} = \frac{20}{2}[2 \times 15 + (20-1) \times 4]\)

\(= 1060\)

Q273. Find the sum of the first 13 terms of the AP: \(a = 15\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{13} = \frac{13}{2}[2 \times 15 + (13-1) \times 4]\)

\(= 507\)

Q274. Find the sum of the first 11 terms of the AP: \(a = 2\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{11} = \frac{11}{2}[2 \times 2 + (11-1) \times 1]\)

\(= 77\)

Q275. Find the sum of the first 5 terms of the AP: \(a = 3\), \(d = 8\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{5} = \frac{5}{2}[2 \times 3 + (5-1) \times 8]\)

\(= 95\)

Q276. Find the sum of the first 10 terms of the AP: \(a = 10\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{10} = \frac{10}{2}[2 \times 10 + (10-1) \times 4]\)

\(= 280\)

Q277. Find the sum of the first 8 terms of the AP: \(a = 6\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{8} = \frac{8}{2}[2 \times 6 + (8-1) \times 6]\)

\(= 216\)

Q278. Find the sum of the first 9 terms of the AP: \(a = 5\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{9} = \frac{9}{2}[2 \times 5 + (9-1) \times 6]\)

\(= 261\)

Q279. Find the sum of the first 16 terms of the AP: \(a = 5\), \(d = 8\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{16} = \frac{16}{2}[2 \times 5 + (16-1) \times 8]\)

\(= 1040\)

Q280. Find the sum of the first 11 terms of the AP: \(a = 1\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{11} = \frac{11}{2}[2 \times 1 + (11-1) \times 1]\)

\(= 66\)

Q281. Find the sum of the first 19 terms of the AP: \(a = 15\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{19} = \frac{19}{2}[2 \times 15 + (19-1) \times 4]\)

\(= 969\)

Q282. Find the sum of the first 14 terms of the AP: \(a = 14\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{14} = \frac{14}{2}[2 \times 14 + (14-1) \times 5]\)

\(= 651\)

Q283. Find the sum of the first 7 terms of the AP: \(a = 8\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{7} = \frac{7}{2}[2 \times 8 + (7-1) \times 7]\)

\(= 203\)

Q284. Find the sum of the first 14 terms of the AP: \(a = 9\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{14} = \frac{14}{2}[2 \times 9 + (14-1) \times 7]\)

\(= 763\)

Q285. Find the sum of the first 20 terms of the AP: \(a = 9\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{20} = \frac{20}{2}[2 \times 9 + (20-1) \times 4]\)

\(= 940\)

Q286. Find the sum of the first 8 terms of the AP: \(a = 3\), \(d = 4\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{8} = \frac{8}{2}[2 \times 3 + (8-1) \times 4]\)

\(= 136\)

Q287. Find the sum of the first 25 terms of the AP: \(a = 14\), \(d = 2\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{25} = \frac{25}{2}[2 \times 14 + (25-1) \times 2]\)

\(= 950\)

Q288. Find the sum of the first 14 terms of the AP: \(a = 8\), \(d = 5\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{14} = \frac{14}{2}[2 \times 8 + (14-1) \times 5]\)

\(= 567\)

Q289. Find the sum of the first 23 terms of the AP: \(a = 7\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{23} = \frac{23}{2}[2 \times 7 + (23-1) \times 7]\)

\(= 1932\)

Q290. Find the sum of the first 7 terms of the AP: \(a = 12\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{7} = \frac{7}{2}[2 \times 12 + (7-1) \times 1]\)

\(= 105\)

Q291. Find the sum of the first 25 terms of the AP: \(a = 2\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{25} = \frac{25}{2}[2 \times 2 + (25-1) \times 1]\)

\(= 350\)

Q292. Find the sum of the first 9 terms of the AP: \(a = 3\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{9} = \frac{9}{2}[2 \times 3 + (9-1) \times 1]\)

\(= 63\)

Q293. Find the sum of the first 21 terms of the AP: \(a = 6\), \(d = 7\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{21} = \frac{21}{2}[2 \times 6 + (21-1) \times 7]\)

\(= 1596\)

Q294. Find the sum of the first 25 terms of the AP: \(a = 4\), \(d = 1\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{25} = \frac{25}{2}[2 \times 4 + (25-1) \times 1]\)

\(= 400\)

Q295. Find the sum of the first 8 terms of the AP: \(a = 15\), \(d = 6\).

Difficulty: Medium · Topic: Sum of first n terms

Solution

\(S_n = \frac{n}{2}[2a + (n-1)d]\)

\(S_{8} = \frac{8}{2}[2 \times 15 + (8-1) \times 6]\)

\(= 288\)

Q296. Find the compound interest on Rs 8000 at 20% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 8000\left(1 + \frac{20}{100}\right)^{2}\)

CI = A - P = 3520.0

Q297. Find the compound interest on Rs 1000 at 20% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 1000\left(1 + \frac{20}{100}\right)^{1}\)

CI = A - P = 200.0

Q298. Find the compound interest on Rs 25000 at 8% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 25000\left(1 + \frac{8}{100}\right)^{1}\)

CI = A - P = 2000.0

Q299. Find the compound interest on Rs 2000 at 20% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 2000\left(1 + \frac{20}{100}\right)^{2}\)

CI = A - P = 880.0

Q300. Find the compound interest on Rs 20000 at 12% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{12}{100}\right)^{1}\)

CI = A - P = 2400.0

Q301. Find the compound interest on Rs 2000 at 8% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 2000\left(1 + \frac{8}{100}\right)^{3}\)

CI = A - P = 519.42

Q302. Find the compound interest on Rs 20000 at 8% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{8}{100}\right)^{3}\)

CI = A - P = 5194.24

Q303. Find the compound interest on Rs 25000 at 8% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 25000\left(1 + \frac{8}{100}\right)^{3}\)

CI = A - P = 6492.8

Q304. Find the compound interest on Rs 10000 at 12% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 10000\left(1 + \frac{12}{100}\right)^{1}\)

CI = A - P = 1200.0

Q305. Find the compound interest on Rs 25000 at 10% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 25000\left(1 + \frac{10}{100}\right)^{1}\)

CI = A - P = 2500.0

Q306. Find the compound interest on Rs 1000 at 8% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 1000\left(1 + \frac{8}{100}\right)^{3}\)

CI = A - P = 259.71

Q307. Find the compound interest on Rs 1000 at 8% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 1000\left(1 + \frac{8}{100}\right)^{2}\)

CI = A - P = 166.4

Q308. Find the compound interest on Rs 5000 at 15% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 5000\left(1 + \frac{15}{100}\right)^{1}\)

CI = A - P = 750.0

Q309. Find the compound interest on Rs 10000 at 5% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 10000\left(1 + \frac{5}{100}\right)^{3}\)

CI = A - P = 1576.25

Q310. Find the compound interest on Rs 5000 at 12% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 5000\left(1 + \frac{12}{100}\right)^{1}\)

CI = A - P = 600.0

Q311. Find the compound interest on Rs 20000 at 20% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{20}{100}\right)^{1}\)

CI = A - P = 4000.0

Q312. Find the compound interest on Rs 25000 at 12% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 25000\left(1 + \frac{12}{100}\right)^{2}\)

CI = A - P = 6360.0

Q313. Find the compound interest on Rs 20000 at 12% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{12}{100}\right)^{2}\)

CI = A - P = 5088.0

Q314. Find the compound interest on Rs 25000 at 15% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 25000\left(1 + \frac{15}{100}\right)^{2}\)

CI = A - P = 8062.5

Q315. Find the compound interest on Rs 20000 at 5% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{5}{100}\right)^{1}\)

CI = A - P = 1000.0

Q316. Find the compound interest on Rs 20000 at 8% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{8}{100}\right)^{1}\)

CI = A - P = 1600.0

Q317. Find the compound interest on Rs 1000 at 15% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 1000\left(1 + \frac{15}{100}\right)^{3}\)

CI = A - P = 520.87

Q318. Find the compound interest on Rs 15000 at 15% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 15000\left(1 + \frac{15}{100}\right)^{2}\)

CI = A - P = 4837.5

Q319. Find the compound interest on Rs 20000 at 8% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{8}{100}\right)^{2}\)

CI = A - P = 3328.0

Q320. Find the compound interest on Rs 5000 at 8% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 5000\left(1 + \frac{8}{100}\right)^{2}\)

CI = A - P = 832.0

Q321. Find the compound interest on Rs 2000 at 5% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 2000\left(1 + \frac{5}{100}\right)^{2}\)

CI = A - P = 205.0

Q322. Find the compound interest on Rs 10000 at 15% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 10000\left(1 + \frac{15}{100}\right)^{1}\)

CI = A - P = 1500.0

Q323. Find the compound interest on Rs 8000 at 15% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 8000\left(1 + \frac{15}{100}\right)^{1}\)

CI = A - P = 1200.0

Q324. Find the compound interest on Rs 2000 at 15% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 2000\left(1 + \frac{15}{100}\right)^{2}\)

CI = A - P = 645.0

Q325. Find the compound interest on Rs 25000 at 10% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 25000\left(1 + \frac{10}{100}\right)^{2}\)

CI = A - P = 5250.0

Q326. Find the compound interest on Rs 15000 at 8% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 15000\left(1 + \frac{8}{100}\right)^{2}\)

CI = A - P = 2496.0

Q327. Find the compound interest on Rs 10000 at 12% per annum for 3 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 10000\left(1 + \frac{12}{100}\right)^{3}\)

CI = A - P = 4049.28

Q328. Find the compound interest on Rs 5000 at 20% per annum for 1 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 5000\left(1 + \frac{20}{100}\right)^{1}\)

CI = A - P = 1000.0

Q329. Find the compound interest on Rs 20000 at 15% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 20000\left(1 + \frac{15}{100}\right)^{2}\)

CI = A - P = 6450.0

Q330. Find the compound interest on Rs 1000 at 5% per annum for 2 years, compounded annually.

Difficulty: Medium · Topic: Compound Interest

Solution

\(A = P\left(1 + \frac{r}{100}\right)^n\)

\(= 1000\left(1 + \frac{5}{100}\right)^{2}\)

CI = A - P = 102.5

Q331. If Sₙ = 3n² + 5n, find the AP and its common difference.

Difficulty: Medium-Hard · Topic: Sum of First n Terms

Solution

a₁ = S₁ = 8. a₂ = S₂−S₁ = 22−8 = 14. d = 14−8 = 6. General: aₙ = Sₙ−Sₙ₋₁ = 3n²+5n−3(n−1)²−5(n−1) = 6n+2. Check: a₁=8, a₂=14 ✓.

Q332. Sum of first n terms of two APs are in ratio (7n+1):(4n+27). Find ratio of their 11th terms.

Difficulty: Medium-Hard · Topic: Sum of First n Terms

Solution

Sₙ ratio: [n/2(2a₁+(n−1)d₁)] / [n/2(2a₂+(n−1)d₂)] = (7n+1)/(4n+27).

For 11th term ratio, put n=21 (since a₁₁ corresponds to the (n+1)/2 = 11th middle term when n=21):

(7×21+1)/(4×21+27) = 148/111 = 4/3.

Q333. The sum of first 6 terms of an AP is 42 and the ratio of its 10th term to its 30th term is 1:3. Find a and d.

Difficulty: Medium-Hard · Topic: nth Term of an AP

Solution

S₆ = 3(2a+5d) = 42 → 2a+5d = 14 ... (i).

a₁₀/a₃₀ = (a+9d)/(a+29d) = 1/3 → 3a+27d = a+29d → 2a = 2d → a = d ... (ii).

From (i): 7d = 14 → d = 2, a = 2.

Q334. A sum of Rs 700 is to be used to give 7 cash prizes. If each prize is Rs 20 less than the preceding prize, find the value of each prize.

Difficulty: Medium-Hard · Topic: Sum of First n Terms

Solution

AP with 7 terms, d = −20, S₇ = 700.

700 = 7/2[2a+6(−20)] = 7/2(2a−120). 200 = 2a−120. a = 160.

Prizes: 160, 140, 120, 100, 80, 60, 40.

Q335. If a, b, c are in AP, prove that a³+c³+6abc = 8b³.

Difficulty: Hard · Topic: Sum of First n Terms

Solution

Since a,b,c are in AP: a+c = 2b.

a³+c³ = (a+c)(a²−ac+c²) = (a+c)[(a+c)²−3ac] = 2b[4b²−3ac].

LHS = 2b(4b²−3ac)+6abc = 8b³−6abc+6abc = 8b³ = RHS. ∎

Other Chapters in Mathematics

Ch 1: Real NumbersCh 2: PolynomialsCh 3: Pair of Linear Equations in Two VariablesCh 4: Quadratic EquationsCh 6: TrianglesCh 7: Coordinate GeometryCh 8: Introduction to TrigonometryCh 9: Some Applications of TrigonometryCh 10: CirclesCh 11: Areas Related to CirclesCh 12: Surface Areas and VolumesCh 13: StatisticsCh 14: Probability

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